Curyfury Posted July 27, 2015 Report Share Posted July 27, 2015 (edited) Now we all know about dissymmetry of lift and teetering theories in helicopters. Now, lets take a standard fix wing airplane and reverse the wing on the left side to act like the retreating blade on an r22. If this plane was dropped from the belly of an airplane like the bell x-1, will it fly? Will the aircraft teeter and balance itself out? Im guessing that this setup cant create lift, even with a propeller up front, but will it at least glide in a controllable manner? Edited July 27, 2015 by Curyfury Quote Link to comment Share on other sites More sharing options...
avbug Posted July 28, 2015 Report Share Posted July 28, 2015 Are you asking if putting one wing on backward on a fixed wing airplane will create a flyable or glideable machine? No, it won't. There's really no comparison with a spinning rotor, especially given that all the aircraft mass is now in the "rotor." It's a very unbalanced mass. An airplane can spin, which is a coupled rolling and yawing motion in a stalled state, with a vertical descent (or horizontal path in the case of a snap-roll), but an airplane is not a helicopter and shouldn't be expected to act the same (even with the radical change of installing one wing backward on the airframe). Quote Link to comment Share on other sites More sharing options...
rotormandan Posted July 28, 2015 Report Share Posted July 28, 2015 A retreating blade still has forward(positive) airspeed relative to the airfoil. A backwards wing on an airplane does not. The rotor blade is not flying backwards. Quote Link to comment Share on other sites More sharing options...
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